68 Reflection and Transmission Coefficients
Here is the full derivation for reflection,  , and transmission,
, and transmission,  , coefficients and how they relate to one another.
, coefficients and how they relate to one another.
      ![Rendered by QuickLaTeX.com \[ R=\frac{A_{Reflected}}{A_{Incident}} \]](https://uw.pressbooks.pub/app/uploads/quicklatex/quicklatex.com-7deae89acfab00dc5391df440b87b87d_l3.png)
      ![Rendered by QuickLaTeX.com \[ T=\frac{A_{Transmitted}}{A_{Incident}} \]](https://uw.pressbooks.pub/app/uploads/quicklatex/quicklatex.com-57a2a47e24359b747b2099c89e9c25c7_l3.png)
We write the wave pressure as
      ![Rendered by QuickLaTeX.com \[ $P=Acos(kx-\omega t+\phi)$ \]](https://uw.pressbooks.pub/app/uploads/quicklatex/quicklatex.com-ae40e75baf306ace4bade3edfe5d1d82_l3.png)
We start with the two equations derived in the main text. The first expresses no net force on the boundary.
 (1)    
The second expresses energy conservation.
 (2)    
First, if we divide the Equation (1) though by  and use the definitions of
 and use the definitions of  and
 and  in terms of the amplitude ratios, we find an equation relating the two coefficients
 in terms of the amplitude ratios, we find an equation relating the two coefficients
 (3)    
From here, we will shorten the subscripts,  ,
,  and
 and  . Next, rewrite equation (2) putting terms involving
. Next, rewrite equation (2) putting terms involving  on the left, and terms involving
 on the left, and terms involving  on the right.
 on the right.
      ![Rendered by QuickLaTeX.com \[ \frac{1}{Z_1}\left(A_i^2-A_r^2\right)=\frac{1}{Z_2}A_t^2 \]](https://uw.pressbooks.pub/app/uploads/quicklatex/quicklatex.com-f1d676773e032fd548a9445bea7c9304_l3.png)
Now divide by 
      ![Rendered by QuickLaTeX.com \[ \frac{1}{Z_1}\left(1-\frac{A_r^2}{A_i^2}\right)=\frac{1}{Z_2}\frac{A_t^2}{A_i^2} \]](https://uw.pressbooks.pub/app/uploads/quicklatex/quicklatex.com-c2b7c9e66fb5677c853c40589e17fe51_l3.png)
Now, multiply by  , and use the definitions of
, and use the definitions of  and
 and  in terms of the amplitude ratios
 in terms of the amplitude ratios
      ![Rendered by QuickLaTeX.com \[ Z_2\left( 1-R^2 \right)=Z_1 T^2 \]](https://uw.pressbooks.pub/app/uploads/quicklatex/quicklatex.com-08f2395fbc6ed580f163ce7423c7ef8a_l3.png)
Now we will factor the quadratic term, and also use the relationship between  and Equation (3) to substitute for
 and Equation (3) to substitute for 
      ![Rendered by QuickLaTeX.com \[ Z_2 (1-R) (1+R)=Z_1 (1+R)^2 \]](https://uw.pressbooks.pub/app/uploads/quicklatex/quicklatex.com-f163e24d607f71a24ede003e37c2a048_l3.png)
Divide through by 
      ![Rendered by QuickLaTeX.com \[ Z_2 (1-R) =Z_1 (1+R) \]](https://uw.pressbooks.pub/app/uploads/quicklatex/quicklatex.com-44c84daa5e243203c26e20ffdf6a31c8_l3.png)
And solve for R
      ![Rendered by QuickLaTeX.com \[ -(Z_2+Z_1)R=Z_1-Z_2 \]](https://uw.pressbooks.pub/app/uploads/quicklatex/quicklatex.com-d4b048f9a9240bb8c9f2ac2e33ed356f_l3.png)
      ![Rendered by QuickLaTeX.com \[ R=\frac{Z_2-Z_1}{Z_1+Z_2} \]](https://uw.pressbooks.pub/app/uploads/quicklatex/quicklatex.com-506320c756dc986d97fbb31160f34e4f_l3.png)
We can find  by using Equation (3)
 by using Equation (3)
      ![Rendered by QuickLaTeX.com \[ T=1+R=1+\frac{Z_2-Z_1}{Z_1+Z_2}=\frac{Z_1+Z_2}{Z_1+Z_2}+\frac{Z_2-Z_1}{Z_1+Z_2} \]](https://uw.pressbooks.pub/app/uploads/quicklatex/quicklatex.com-c1985f1deb642c8c3ecc8bdbfd5f13f6_l3.png)
      ![Rendered by QuickLaTeX.com \[ T=\frac{2 Z_2}{Z_1+Z_2} \]](https://uw.pressbooks.pub/app/uploads/quicklatex/quicklatex.com-4a1efe9eb35baa834157377b2eaa1f18_l3.png)
